题目1234567891011输入 n 个整数,找出其中最小的 k 个数。注意:输出数组内元素请按从小到大顺序排序;数据范围1≤k≤n≤1000样例输入:[1,2,3,4,5,6,7,8] , k=4输出:[1,2,3,4]题解点击查看1234567891011121314151617181920212223242526272829303132333435363738394041//小根堆class Solution {public: vector<int> getLeastNumbers_Solution(vector<int> input, int k) { priority_queue<int, vector<int>, greater<int>> heap; vector<int> res; for(auto c : input){ heap.push(c); } for(int i = 0; i < k;++i){ res.push_back(heap.top()); heap.pop(); } return res; }};//大根堆class Solution {public: vector<int> getLeastNumbers_Solution(vector<int> input, int k) { priority_queue<int> heap; vector<int> res; for(auto x : input){ heap.push(x); if(heap.size() > k) heap.pop();//如果堆中元素的数量大于k,那就弹出其中最大的数,这样就可以保证堆中始终是最小的k个数 } while(heap.size()){ res.push_back(heap.top()); heap.pop(); } reverse(res.begin(), res.end()); return res; }};